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[已解决]swift 把函数当作(callback,handler的)参数

Swift crifan 3333浏览 0评论
写了个函数,带函数的参数的:
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func getUrlRespJsonDict_async(url:String, respJsonDictHandler:((JSON?) -> Void)) {
    var decodedJsonDict:JSON?
 
    let params:Dictionary<String, AnyObject>? = nil
 
 
    do {
        let opt = try HTTP.GET(
            url,
            parameters: params,
            requestSerializer: JSONParameterSerializer())
 
        opt.start { response in
            if let err = response.error {
                print("error: \(err.localizedDescription)")
                return
            }
 
            print("response.statusCode=\(response.statusCode)")
            print("opt finished: \(response.description)")
 
            decodedJsonDict = JSON(data: response.data)
            print("decodedJsonDict=\(decodedJsonDict)")
 
            respJsonDictHandler(decodedJsonDict)
        }
    } catch let httpGetError {
        NSLog("http get url=\(url) with params=\(params) got error= \(httpGetError)")
    }
}
但是之前去调用却不行
但是现在调用又好了:
可以编译通过了:
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func fetchTeamItemList_async() {
    。。。
    getUrlRespJsonDict_async(fullFetchTeamIdListUrl, respJsonDictHandler: teamItemJsonDictHandler)
}
 
func teamItemJsonDictHandler(respJsonDict:JSON?) {
    。。。
}

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