标签：‘init(start:end:)’ is deprecated: it will be removed in Swift 3. Use the ‘..<‘ operator.

crifan 9年前 (2016-03-29) 1567浏览 0评论

代码：         firstChar = str[Range(start: str.startIndex, end: str.startIndex.advancedBy(1))] 警告： ‘init(start:end:...